Question

DAU COROANA!!! AM NEVOIE DE ACEST EX URGENT!!​

Answer 1

Răspuns:

a)[(4/12)^4:(1/3)^2-(8/24)^5:(3/9)^3]^3:[(-11/12)^2]^5=

[(4/12)^4·(3)^2-(8/24)^5·(9/3)^3]^3:(-11/12)^10=

(1^6-1^8)^3:(-11/12)^10=

0:(-11/12)^10=0

b)[(-3/4)^6:(3/4)^4+(1/2)^7:(1/2)^5]^3·(39/16)^1=

[(-3/4)^6·(4/3)^4+(1/2)^7·(2)^5]^3·39/16=

(-1^10+1^12)^3·39/16=

1·39/16=39/16

sper că te-am ajutat!!