Question

Dau coroana. Calculati, respectend regulile invatate. a) [267+117x9-(832:2-531:9)]x10= b) 30+4x[36:9+3x(20+8x42:2)]= c)[2100:(225-500:4)+(84:2x0)]x100:10:10= d)9x(101x1+111:1)-[85-7x(36:9+63:9)]= e) 3+6x[30+6x(3+5x6)-28]-3= f)2+2x[2+3x(2+3x(2+202:2-306:3)]=

Answer 1

a)
[267+117x9-(832:2-531:9)]x10=
[267+117x9-(416-59)]x10=
(267+119x9-357)x10=
(267+1071-357)x10=
381x10=3810

b)30+4x[36:9+3x(20+8x42:2)]=
30+4x[36:9+3x(20+336:2)]=
30+4x[36:9+3x(20+168)]=
30+4x(36:9+3x188)=
30+4x(4+564)
30+4x568=
30+2272=2302

c)[2100:(225-500:4)+(84:2x0)]x100:10:10=
[2100:(225-125)+0]x100:10:10=
(2100:100)x100:10:10=
21x100:10:10=
2100:10:10=
210:10=21

d)9x(101x1+111:1)-[85-7x(63:9)]=
9x(101+111)-[(85-7x7)]=
9x212-(85-49)=
9x212-36=
1908-36=1872

e)3+6x[30+6x(3+5x6)-28]-3=
3+6x[30+6x(3+30)-28]-3=
3+6x(30+6x33-28)-3=
3+6x(30+198-28)-3=
3+6x200-3=
3+1200-3=1200

f)2+2x[2+3x(2+3x(2+202:2-306:3)]=
2+2x[2+3x(2+3x(2+101-102])=
2+2x[2+3x(2+3x1)]=
2+2x[2+3x(2+3)]=
2+2x(2+3x5)=
2+2x(2+15)=
2+2x17=
2+34=36