Question

dau coroana celui/celei care ma ajuta​

Answer 1

Răspuns:

11.f(1/2)=√2*1/2+3)=√(1+3)=√4=2

f(3)=√(2*3+3)=√9=3

f(11)=√(2*11+3)=√25=5

IMf={2,3,5}

12)f(-x)=√(3(-x)²+1]=√(3x²+1)=f(x)

f(x)=f(-x)   functie     para

13)f(-x) =[2(-x)³-(-x)]/[(-x)²+1]=

[-2x³+x)/(x²+1)= -(2x³-x)/(x²+1)=- f(x)

f(-x)=-f(x) functie impara

Explicație pas cu pas: