Question

Dau coroana cine ma ajuta la 5.
Ajutati-ma va rog.

Answer 1

Răspuns:

m∡(AOC)=m∡(AOB)+40°

m∡(AOB)=m∡(BOC)×2⇒m∡(AOC)=m∡(BOC)×2+40°

360°=m∡(BOC)+m∡(BOC)×2+m∡(BOC)×2+40°

m∡(BOC)=320°/5=64°

m∡(AOB)=64°×2=128°

m∡(AOC)=128°+40°=168°