Question

dau coroana
daca x-4=3 si x²-4=12,determinati numarul
a=(x+4)+(x+4)²+(x+4)³

Answer 1

x-4=3

x=3+4

x=7

x^2-4= 12

x^2=12+4

x^2=16

x=4

a=(x+4)+(x+4)^2 +(x+4)^3

a=4+4+16+16+64+64

a=168