Question

Dau coroana,e urgent!!​

Answer 1

Răspuns:

A

Explicație pas cu pas:

$a = \dfrac{1}{ \sqrt{3} } - \dfrac{2^{(2} }{ 2\sqrt{3} } + \dfrac{1}{ 3\sqrt{3} } = \dfrac{1}{ \sqrt{3} } - \dfrac{1}{ \sqrt{3} } + \dfrac{1}{ \sqrt{27} } = \dfrac{1}{ 3\sqrt{3} }$

$b = \dfrac{ ^{2)} \sqrt{6} }{ 2\sqrt{2} } + \dfrac{3\sqrt{6} }{4\sqrt{2} } = \dfrac{2 \sqrt{6} + 3\sqrt{6} }{4\sqrt{2} } = \dfrac{5\sqrt{6}^{( \sqrt{2} } }{4\sqrt{2} } = \dfrac{5\sqrt{3} }{4}$

$a \cdot b = \dfrac{1}{ 3\sqrt{3} } \cdot \dfrac{5\sqrt{3} }{4} = \bf \dfrac{5}{12}$