Question

DAU COROANA, E URGENT!!!

Answer 1

a)

n = m/miu = N/N.A., unde N.A. = nr. lui Avogadro = 6,022x10la23 molecule

=> m  = miuxN/N.A.  = 28x3,01x10la24/6,022x10la23 =

= 140 g N2

b)

PV = nRT => V = nRT/P, 1 kPa = 0,01 atm

n = 3,01x10la24/6,022x10la23 = 5 moli N2

=> V = 5x0,082x(273+27)/1,5 = 82 L

1 mol N2 ............ 22,4 L ............... 6,022x10la23 molecule

                          82 L ................... n = 2,2x10la24 molecule

c)

N.final = 40/100xN = 0,4x2,2x10la24 = 8,82x10la23 molecule

d)

P1V = n1RT

n1 = 8,82x10la23/6,022x10la23 = 1,46 moli

=> P1 = n1RT/V = 1,46x0,082x300/82 = 0,438 atm