Question

DAU COROANA
Exercitiul 2

Answer 1

a)x+0,5=2,8=>x=2,3∈Q
b)x-3/4=5/2=>x=5/2(amplifici cu 2)+3/4=>x=13/4∈Q
c)5*1/3-x=4(amplifici cu 3)=>16/3-x=12/3=>x=4/3∈Q
d)0,(6):x=3=>6/9:x=3=>2/3:x=3=>x=(2*3)/3=>x=2∈N
e)x:16/10=13/6=>x=13/6*16/10=>x=52/15∈Q
f)0,1(3)*x=1/3=>13/90*x=1/3=?x=1/3:13/90=>x=1/3*90/13=>x=30/13∈Q
g)3x/2(amplifici cu 3)+1/2(amplifici cu 3)=5/3(amplifici cu 2)=>9x+3=10(ptr ca dispare numitorul)=>9x=7=>x=7/9∈Q
h)2*1x/2(amplifici cu 2)-1/4=6(amplifici cu 4)=>10x-1=24=>10x=25=>x=2,5∈Q
i)0,4-0,2x=0,1=>4/10-2/10=1/10=>4-2x=1=>3=2x=>x=3/2∈Q