Question

dau coroana
fie functia f: R-R ,f(x) = -2x+3.Determinati valorile reale ale lui x ,pentru care functia f ia valori nenegative.

Answer 1

-2x+3≥0

3≥2x

$\frac{3}{2} \geq x$

x∈(-∞; $\frac{3}{2}$]

Answer 2

f(0)=-2x0+3
f(0)=0+3
f(0)=3
f(1)=-2x1+3
f(1)=-2+3
f(1)=1
x=0,1
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