Question

DAU COROANA !!
Indicati coeficientii a,b si termenul liber c ai ecuatiei:
a)3x² - 4x - 4 = 0
b)5x² + 3x = 0
c)x² - x - 2 = 0

Answer 1

a)$3 x^{2} -4x-4=0$  a=3 b=-4 c=-4   Δ =b²-4ac Δ=16+48 =64      x1 = $\frac{4+8}{6 } = \frac{12}{6} = 2$   x2= $\frac{4-8}{6} = \frac{-4}{6} = \frac{-2}{3}$        b)5x²+3x=0 Δ=b²-4ac  Δ = 9-0 = 9   x1= $\frac{-3+3}{10} = 0$   si x2= $\frac{-3-3}{10} = \frac{-6}{10 } = \frac{-3}{5}$   c) x²-x-2 =0  Δ=b²-4ac Δ = 1+8 = 9   x1 =$\frac{1+3}{2} = \frac{4}{2} =2$  si x2 = $\frac{1-3}{2} = \frac{-2}{2} = -1$