Question

dau coroana nu dati raspunsuri gresite !!​

Answer 1

Răspuns:

Explicație pas cu pas:

a) (1/2)^7

1/( 2^7)=1/128

b)(2/3)^5=2^5/3^5=32/243

c) (4/9)^3=4^3/9^3=64/729

d) 11^3/7^3=1331/343

e) 5^4/4^4=625/256

f) (3/3)^2017=1^2017=1

g)19/43

h) orice nr.ridicat la puterea 0 este 1

deci  (2011/2017)^0=1

Answer 2

Răspuns:

$(\frac{1}{2}) ^{7} =\frac{1}{128} \\\\(\frac{2}{3} )^{5} =\frac{2^{5} }{3^{5} } =\frac{32}{243} \\\\(\frac{4}{9} )^{3}=\frac{64}{729} \\\\(\frac{11}{7} )^{3} =\frac{1331}{343} \\\\(\frac{5}{4} )^{4} =\frac{625}{256} \\\\(\frac{3}{3})^{2017} =1^{2017} =1\\\\(\frac{19}{43})^{1} =\frac{19}{43} \\\\(\frac{2011}{2017})^{0} =1$