Question

dau coroana, repede.​

Answer 1

a=l√12-4l+4/(4-√12)+10

√12-4<0

a=4-√12+4/(4-√12)+10=

[(4-√12)²+4+10(4-√12)]/(4-√12)=

(4-√12)(10-4√3)/(4-√12)=

a=10-4√3

b=l2√2-3 l -1/(3-2√2)+√32+√(-8)²

2√2-3<0

b=3-2√2-1/(3-2√2)+√2⁵+√(2³)²

raționalizăm numitorul

(3+2√2)/(9-8)=(3+2√2)

b=3-2√2-3-2√2+4√2+8=8

b=8

m a.=(10-4√3+8)/2=(18-4√3)/2

m.a=9-2√3

m g.=√8(10-4√3)=√(80-32√3)=

4√(5-2√3)

c²=25-12=4

√(5-2√3)=√(5-2)/2-√(5+2)/2=

m.g.=√3/2-√7/2