Question

Dau coroana si cont de fortnite! ​

Answer 1

a)

$^{6)} 1 - \dfrac{^{3)}1}{2} - \dfrac{^{2)}1}{3} - \dfrac{1}{6} = \dfrac{6-3-2-1}{6} = \dfrac{6-6}{6} = \dfrac{0}{6} = \bf 0$

b)

$\dfrac{^{6)}1}{5} - \dfrac{^{3)}1}{10} + \dfrac{^{2)}1}{15} = \dfrac{6-3+2}{30} = \dfrac{5^{(5} }{30} = \bf \dfrac{1}{6}$

c)

$\bigg(1 - \dfrac{1}{3}\bigg)+\bigg(2 - \dfrac{2}{3}\bigg)+\bigg(2 - \dfrac{1}{3}\bigg)+\bigg(1 - \dfrac{2}{3}\bigg) = 1 + 2 + 2 + 1 - \bigg(\dfrac{1}{3} + \dfrac{2}{3} + \dfrac{1}{3} + \dfrac{2}{3}\bigg) =$

$= 6 - \dfrac{1 + 2 + 1 + 2}{3} = 6 - \dfrac{6}{3} = 6 - 2 = \bf 4$

d)

$\bigg(3\dfrac{1}{2} - \dfrac{1}{2}\bigg) + \bigg(3\dfrac{1}{3} - \dfrac{1}{3}\bigg) = \bigg(\dfrac{7}{2} - \dfrac{1}{2}\bigg) + \bigg(\dfrac{10}{3} - \dfrac{1}{3}\bigg) =$

$= \dfrac{7 - 1}{2} + \dfrac{10 - 1}{3} = \dfrac{6}{2} + \dfrac{9}{3} = 3 + 3 = \bf 6$