Question

dau coroana si multumesc

Answer 1

a)m(∡AOB)+m(∡COD)= 360°- 2x90°= 180°
b)m(∡AOD)=m(∡AOB)+90°     l
m(∡COB)=m(∡AOB)+90°        l⇒∡AOD≡∡COB

Answer 2

M(AOB)+m(COD)=360°-2x90°=180°
b)m
b)