Question

Dau coroana!!! Un biciclist parcurge un drum in trei zile, astfel: in prima zi o treime din lungimea drumului , a doua zi doua cincimi din rest, iar in a treia zi , ultimii 24 de km. Determinati lungimea drumului si aflati cati kilometri a parcurs biciclistul in fiecare dintre zile.

Answer 1

x=drum
prima zi =x/3
a doua zi =(x-x/3)*2/5=2x/3*2/5=4x/15
x/3+4x/15+24=x
inmultim ecuatia cu 15
5x+4x+24*15=15x
9x+360=15x
15x-9x=360
6x=360
x=360:6
x=60km
prima zi x/3=60/3=20km
a doua zi 4*60/15=4*4=16km

Answer 2

1)  x/3  ;      x-x/3 =3x/3-x/3 =2x/3   rest
2)2/5 *2x/3 =4x/15
3) 24 km

x/3+4x/15+24 =x  numitor 15
5x+4x+360 =15x
15x+5x+4x=360
6x =360
x =60 km

1)  x/3 =60/3 =20 km
2)  4x/15 =240/15 =16 km
3)   24 km
v  ;    20+16+24 =60 km