Question

dau coroana urgent!!!!​

Answer 1

a. ascuțit- <CBD

obtuz - <CBE

alungit- <ABE

drept - <DBE

b. m(<ABC)+m(<CBD)+m(<DBE)=180°

Dar m(<DBE)=90°

m(<CBD)=35° 15'

=> m(<ABC)+35° 15' +90°=180°

m(<ABC) =90°-35° 15'

m(<ABC)= 64° 45'

m(<CBE)=m(<CBD)+m(<DBE)

m(<CBE)=90°+ 35° 15'

m(<CBE)= 125° 15'