Question

Dau coroana Urgent. Rezolvați va rog

Answer 1

${3}^{ - 5} \times {9}^{2} = \\ {3}^{ - 5} \times ( {3}^{2} ) {}^{2} = \\ {3}^{ - 5} \times {3}^{4} = \\ {3}^{ - 1} = \\ \frac{1}{3}$

${81}^{ - 2} \div {27}^{ - 3} = \\ ( {3}^{4} ) {}^{ - 2} \div ( {3}^{3} ) {}^{ - 3} = \\ {3}^{ - 8} \div {3}^{ - 9} = \\ 3$

$\frac{ {6}^{4} \times {9}^{ - 3} }{ {4}^{2} } = \\ \frac{ {6}^{4} }{ {4}^{2} \times {9}^{ 3} } = \\ \frac{ {6}^{4} }{16 \times {9}^{3} } = \\ \frac{1296}{16 \times {9}^{3} } = \frac{81}{ {9}^{3} } = \frac{ {9}^{2} }{ {9}^{ 3} } = \frac{1}{9}$

Answer 2

Răspuns:

3^-5x9²

3^-5x3⁴

3^-1

1/3

81^-2:27^-3

3^-8:3^-9

3^(-8+9)

3¹=3

(6⁴x9^-3)/4²

6⁴/(16x9³)

1296/(16x9³)

81/9³

9²/9³

1/9