Question

dau coroana!! urgent!
Sa se afle x din egalitatile:
a) 320:{[340-(120-4 ori x)]:10+6}=10.
b) {250-[175:(729:x+15) + 3]x5}:10=20.
c) 30-{[(2 ori x-8 )x2-12]:4 - 1}x10=20
Va rog! dau coroana,si puncte!!

Answer 1

a) 320:{[340-(120- 4 * x)]:10+6}=10.
10*{[340-(120-4x)]:10+6}=320
[340-(120-4x)]:10+6=32
[340-(120-4x)]:10=32-6
[340-(120-4x)]:10=26
340-(120-4x)=26*10
340-(120-4x)=260
120-4x=340-260
120-4x=80
4x=120-80
4x=40
x=40:4
x=10

b) {250-[175:(729:x+15) + 3]x5}:10=20.
250-[175:(729:x+15) + 3]x5=200
[175:(729:x+15) + 3]x5=50
[175:(729:x+15) + 3]=50:5
175:(729:x+15) + 3=10
175:(729:x+15)=7
729:x+15= 175:7
729:x+15= 25
729:x=25-15
729:x=10
10x=729
x=72,9

c) 30-{[(2* x-8 )x2-12]:4 - 1}x10=20
{[(2* x-8 )x2-12]:4 - 1}x10=30-20
{[(2* x-8 )x2-12]:4 - 1}x10=10
[(2* x-8 )x2-12]:4 - 1= 10:10
[(2* x-8 )x2-12]:4 - 1=1
[(2* x-8 )x2-12]:4 =1+1
[(2* x-8 )x2-12]:4 =2
(2* x-8 )x2-12=4*2
(2* x-8 )x2-12=8
(2* x-8 )x2=12+8
(2* x-8 )x2=20
2* x-8 =20:2
2* x-8 =10
2x=10+8
2x=18
x=18:2
x=9