Question

dau coroana urgent :
Scoateti factor comun pe (x+1)

a) 3(x+1)+a(x+1)
b) -4a(x+1)+2b(x+1)
c) (x+1)·x+3·(x+1)
d) (x+1)(x-2)+(x+1)(2x+3)
e) (a-2)(x+1)+4a(x+1)
f) (x+1)(6x-7)-(6x-8)(x+1)

Answer 1

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Answer 2

Răspuns:

a)   (x+1)(3+a)    b)  (x+1)(2b-4a)   ;  c)   (x+1)(x+3) ;   d )   (x+1)(x-2+2x+3)=(x+1)(3x+1 e )  (x+1)(a-2+4a) =(x+1)(5a-2) ;     f) (x-1)(6x-7-6x+8)=x+1

Explicație pas cu pas: