Question

Dau coroana!!!!
Va rog !!!

Answer 1

$\frac{\overline{ab0}}{c}-10+\frac{\overline{bc}}{a}=82\\ \frac{\overline{ab0}}{c}+\frac{\overline{bc}}{a}=92\\ \frac{\overline{ab0}}{c}+^{c)}1+\frac{\overline{bc}}{a}=93\\ \frac{\overline{abc}}{c}+\frac{\overline{bc}}{a}=93|+100\\ \frac{\overline{abc}}{c}+^{a)}100+\frac{\overline{bc}}{a}=193\\ \frac{\overline{abc}}{c}+\frac{\overline{abc}}{a}=193$
$\overline{abc}(a+c)=193ac\\ 193|\overline{abc}\\ 1)\overline{abc}=193\\ a=1,c=9, 1+9 \neq 1\cdot9\\ 2\overline{abc}=2\cdot 193=386\\ a=3,c=6, 2(3+6)=3\cdot6\\ \overline{abc}=386\\ 3)\overline{abc}=3\cdot193=579\\ a=5,c=9,3(5+9) \neq 5\cdot9$
$4)\overline{abc}=4\cdot193=772\\ a=7,c=2\\ 4(7+2) \neq 7\cdot2\\ 5)\overline{abc}=5\cdot193=965\\ a=9,c=5\\ 5(9+5) \neq 9\cdot5$
prin urmare avem solutia unica 386