Question

Dau coroana va rog e urgent!!!!!!

Answer 1

Răspuns:

a.

-3x+2<-7

-3x<-9

x<3 => x apartine (-infinit,3)

b.

3(x-1)>2x+9

3x-3>2x+9

x>12 =>x apartine (12,+infinit)

c.

4(3x+2)-14x>69-3(2x+3)

12x+8-14x>69-6x-9

2x+8>-6x+60|:2

x+4>-3x+30

4x>26

x>13/2 =>x apartine(13/2,+infinit)

d.

[3(x-4)-5(x+4)]/(-2)<3|*(-2)

3(x-4)-5(x+4)>-6

3x-12-5x-20>-6

-2x>-34

x<17 =>x apartine(-infinit,17)

e.

[2(1-x)+3x-5]/(-2)<1|*(-2)

2(1-x)+3x-5>-2

2-2x+3x-5>-2

x>1 =>x apartine(1,+infinit)

f.

[9-5x+2(x+3)]/(-3)<2|*(-3)

9-5x+2(x+3)>-6

9-5x+2x+6>-6

-3x>-21

x<7 =>x apartine(-infinit,7)