Question

dau coroana va rog ex 2​

Answer 1

Răspuns:

$a=\dfrac{1}{\sqrt{2} }+ \dfrac{2}{\sqrt{8} }=\dfrac{1}{\sqrt{2} }+ \dfrac{2}{\sqrt{4*2} }=\dfrac{1}{\sqrt{2} }+ \dfrac{2}{2\sqrt{2} }=\dfrac{1}{\sqrt{2} }+ \dfrac{1}{\sqrt{2} }=\dfrac{2}{\sqrt{2}}=\dfrac{2\sqrt{2} }{(\sqrt{2})^{2}}=\dfrac{2\sqrt{2} }{2}=\sqrt{2}.\\b=\sqrt{25*2}+\sqrt{9*2}=5\sqrt{2}+3\sqrt{2}=8\sqrt{2}.\\mg=\sqrt{a*b}=\sqrt{\sqrt{2}*8\sqrt{2}} =\sqrt{8*(\sqrt{2})^{2}}=\sqrt{8*2}=\sqrt{16}=4.$

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