Question

dau coroana va rog frumos

Answer 1

1/3×{1/3×[1/3×(x/3-1)+1]+1}+2=3
1/3×{1/3×[1/3×(x/3-1)+1]+1}=3-2
1/3×{1/3×[1/3×(x/3-1)+1]+1}=1
1/3×[1/3×(x/3-1)+1]+1=3
1/3×[1/3×(x/3-1)+1]=3-1
1/3×[1/3×(x/3-1)+1]=2
[1/3×(x/3-1)+1]=6
1/3×(x/3-1)=6-1
1/3×(x/3-1)=5
x/3-1=15
x/3=16
x=16×3
x=48

3,(3)=(33-3)/9=30/9=10/3
0,(6)=6/9=2/3
3,(3)·x+2·x-0,(6)=1-2·(x+1)+2,3
10x/3+2x-2/3=1-2x-2+23/10
10x/3+4x=-1+23/10+2/3
100x+120x=-30+69+20
220x=59
x=59/220


3 1/3=10/3
1 3/4=7/4
2 2/5=12/5
1 1/4=5/4
1 2/3=5/3
10/3:{[7/4:(12/5-5x/4)]×1/7+5/3}=1
{[7/4:(12/5-5x/4)]×1/7+5/3}=10/3
[7/4:(12/5-5x/4)]×1/7=10/3-5/3
[7/4:(12/5-5x/4)]×1/7=5/3
7/4:(12/5-5x/4)=5/3:1/7
7/4:(12/5-5x/4)=35/3
12/5-5x/4=7/4:35/3
12/5-5x/4=7/4 ×3/35
12/5-5x/4=3/20
5x/4=12/5-3/20
5x/4=(48-3)/20
5x/4=45/20
5x/4=9/4
5x=9
x=9/5