Question

Dau coroana, va rog rezolvati exercițiul.

(4√3-7)² + √(5√2-7)²​

Answer 1

$\it (4\sqrt3-7)^2+\sqrt{(5\sqrt2-7)^2}=(4\sqrt3)^2-2\cdot4\sqrt3\cdot7+7^2+|5\sqrt2-7|=\\ \\ \\ =48-56\sqrt3+49+5\sqrt2-7=90-56\sqrt3+5\sqrt2$

$\it 5\sqrt2 > 5\cdot1,4 \Rightarrow 5\sqrt2 > 7\bigg|_{-7} \Rightarrow 5\sqrt2-7 > 0 \Rightarrow |5\sqrt2-7|=5\sqrt2-7$