Question

dau coroana va rog sub 1 ex 4

Answer 1

Răspuns:

AB^2+BC^2=AC^2

m(A)=90 grade

=>M(B)=M(C)=45 grade

Sinα=c.o/ip

sinc=45 grade

=>

sinc=c.o/ip

sin45=1/√2

1/√2=5/ip

1/√2*ip=5

ip=5/(1/√2)

ip=5√2

Answer 2

Răspuns:

AB^2+BC^2=AC^2

m(<A)=90°

=>

m(<B)=m(<C)=90/2=45°

Sina=c.o/ip

Sinc=45°

=>

Sin45=

$\frac{1}{ \sqrt{2} }$

$\frac{1}{ \sqrt{2} }$*ip=5

ip=

$5 \sqrt{2}$

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