Matematică, întrebare adresată de JAJA112, 9 ani în urmă

DAU COROANA VA ROG VREAU SA FIE REZOLVAT PANA PE DATA DE 12.11.2017 EX 11. 12 13 15

Anexe:

Ahmed1985: Coroana dacă te am ajutat :)
Ahmed1985: Hehe unde e coroana ? Am nevoie și eu dacă poți te rog
JAJA112: de ce ai nevoie
JAJA112: coroana se da dupa 24 de ore
JAJA112: si ori cum iti dau coroana
JAJA112: JUR
Ahmed1985: Ms

Răspunsuri la întrebare

Răspuns de Ahmed1985
1
11))
[(1/3)^0-(1/3)^1-(1/3)^2-(1/3)^3-(1/3)^4]:(1/3)^5
= [1- 1/3 - 1/9-1/27-1/81]:1/243
= [243/243- 81/243 - 27/243 - 9/243 - 3/243]:1/243
= 123/243 : 1/243
= 123
----------
12))
(5/3)^7 x (5/3)^6+(3/4)^15 x (3/4)^19 : (3/4)^16-(5/3)^8 x(5/3)^5- 3^18/2^36
= (5/3)^13 + (3/4)^15+19-16) -(5/3)^13 - 3^18/2^36
= (5/3)^13 + (3/4)^18 - (5/3)^13 - 3^18/2^36
= (3/4)^18 - 3^18/2^36
= 3^18/(2^2)^18 - 3^18/2^36
= 3^18/2^36 - 3^18/2^36 = 00000
----
13)))
(1/3)^50 x (1/5)^49:(1/15)^50
= (1/3)^50 x (1/5)^49 : ( 1/3)^50 x (1/5)^50
= 1x(1/5)^-1 = (1/5)^-1
b))
[(2/5)^20 +(2/5)^21+ (2/5)^22]:(4/25)10
= (2/5)^20.[(2/5)+ (2/5)^2+1]:(4/25)10
= (2/5)^20 [ 10/25+ 4/25+ 25/25]:(4/25)^10
= (2/5)^20x 39/25:(4/25)^10
= (4/25)10 X 39/25 : (4/25)^10
= 39/25 #
--------
14))
(3/5)^30 : 3^32+ 6^32/5^32+10^32
= (3/5)^30 : 9^32/15^32
= (3/5)^30 : (9/15)^32
= (3/5)^30 : (3/5)^29
= 3/5 #
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