Question

dau COROANAA PLSS! [tex]E(x)= ( \frac{x}{ x^{2}-1 }
- \frac{6}{ x^{2}+2x+1 }) * \frac{x-1}{x-3} [/tex]
A) Obtineti forma
cea mai simpla a expresiei
B)Rezolvati in R inecuatia...

Answer 1

E(x)=[x/(x²-1) -6/(x²+2x+1)] * (x-1)/(x-3)
[x/(x²-1) -6/(x²+2x+1)] * (x-1)/(x-3) =
=[x/(x-1)(x+1) -6/(x+1)²] * (x-1)/(x-3) =
=(x²+x-6x+6)/(x-1)(x+1)² * (x-1)/(x-3) =
=(x²-5x+6)/(x+1)² * 1/(x-3) =
=(x-2)(x-3)/(x+1)² * 1/(x-3) =
=(x-2)/(x+1)²
x≠-1
x∈R\{-1}