Question

DAU CORONITA :
A) (X+1)+(x+2)+...(x+41)=40x+860
B) __ _ 5 __
√48 : √3 + ----- X √10
_
√5

Answer 1

A) $(x+1)+(x+2)+...+(x+41)=40*x+860$

$41*x+1+2+...+41=40*x+860$

$41*x+\frac{41*42}{2} =40*x+860$

$41*x+41*21=40*x+860$

$41*x+861=40*x+860$

$41*x-40*x=860-861$

$x=-1$

B) Nu inteleg o iota din ce e scris acolo.