Question

dau coronița,am nevoie de ajutor la mate ​

Answer 1

Explicație pas cu pas:

$\sin^{2} (x) - \sin(x) = \cos^{2} (x)$

$\sin^{2} (x) - \sin(x) = 1 - \sin^{2} (x)$

$2\sin^{2} (x) - \sin(x) - 1 = 0$

$(2\sin(x) + 1)(\sin(x) - 1) = 0$

$0 < x < \pi$

=>

$2\sin(x) + 1 = 0 = > \sin(x) = - \frac{1}{2} \\ fara \: solutie$

$\sin(x) - 1 = 0 = > \sin(x) = 1 \\ = > x = \frac{\pi}{2}$