Question

Dau cororana rezolvare completa Va rog​

Answer 1

Răspuns: a)AP≡AB

∡ABC=∡APD=90°(PD⊥AC)

∡BAC≡∡DAP

de aici ⇒(prin cazul L.U.L)ΔABC≡ΔAPD

b) ΔABC≡ΔAPD⇒AC≡AD

∡BAC=60°

de aici ⇒ΔACD-echilateral

c)CB⊥AD⇒CB-inaltime in ΔACD

PD⊥AC⇒PD-inaltime in ΔACD

BC∩PD={H}

de aici⇒H-ortocentrul ΔACD⇒AH⊥CD

sper ca am ajuat!