Question

dau multe puncte, ajutor plssssss​

Answer 1

Răspuns:

a)

$19 \times 98 - 58 \times 19 = 19(98 - 58) = 19 \times 40 = 760$

b) aici sunt 2 moduri (am sa le notez cu x si y)

x:

$(83 - 25) \times 2 = 58 \times 2 = 116$

y:

$(83 - 25) \times 2 = (83 \times 2) - (25 \times 2) = 166 - 50 = 116$

c)

$803 - 5 \times (256 - (12^{2} + {4}^{3} )) = 803 - 5 \times (256 - (12^{2} + 2^{6} )) = 803 - 5 \times (256 - (12^{2} + 64)) = 803 - 5 \times (256 - 12^{2} - 64) = 803 - 5 \times (192 - 12^{2} ) = 803 - 960 + 5 \times 12^{2} = 803 - 960 + 5 \times 144 = 803 - 960 + 720 = 563$

Answer 2

$\bf c)\\ \\ \it803-5\cdot\[[256-(12^2-4^3)]=803-5\cdot\[[256-(144+64)]=\\ \\ =803-5\cdot(256-208)=803-5\cdot48=803-249=563$