Question

dauu coroana
amplificati raportul algebric;
x+3catre 2x-1 cu 2x+1

Answer 1

$\frac{x+3}{2x-1}= \frac{(x+3)(2x+1)}{(2x-1)(2x+1)}= \frac{ 2x^{2}+x+6x+3 }{ 4x^{2}-1 }= \frac{ 2x^{2}+7x+3 }{ 4x^{2}-1 } .$