Question

De aflat Medianele si Bisectoarele!!! URGENT !!!!

Answer 1

Răspuns:

$a=6;b=8;c=12$

$ma=\sqrt{\frac{2(b^2+c^2)-a^2}{4}=\frac{2(64+144)-36}{4}=\frac{2*208-36}{4}=\frac{416-36}{4}=\frac{380}{4}=95 } \\ma=\sqrt{95}$

$p =$ semiperimetrul

$p=\frac{a+b+c}{2}=\frac{6+8+12}{2}=\frac{26}{2}=13$

$lc=\sqrt{\frac{4ab}{(a+b)^2}*p(p-c)=\frac{4*6*8}{14^2}* 13(13-12)=\frac{192}{196}*13*1= \frac{48}{49}*13=\frac{624}{49}}$

$lc=\frac{\sqrt{694} }{7}$