Question

De calculat:
$b)4 \sqrt{18 } - 2 \sqrt{8} - \sqrt{3} (3 \sqrt{12} - 1)$
va rog frumos!!​

Answer 1

$4 \sqrt{18} - 2 \sqrt{8} - \sqrt{3} (3 \sqrt{12} - 1) = \\ = 4 \sqrt{3 {}^{2} \times 2 } - 2 \sqrt{2 {}^{2} \times 2 } - \sqrt{3} \times 3 \sqrt{12} + \sqrt{3} \\ = 4 \times 3 \sqrt{2} - 2 \times 2 \sqrt{2} - 3 \sqrt{36} + \sqrt{3} \\ = 12 \sqrt{2} - 4 \sqrt{2} - 3 \times 6 + \sqrt{3} \\ = 8 \sqrt{2} - 18 + \sqrt{3}$

Answer 2

$4 \sqrt{18} - 2 \sqrt{8} - \sqrt{3} (3 \sqrt{12} - 1) \\ = 12 \sqrt{2} - 4 \sqrt{2} - \sqrt{3} (6\sqrt{3} - 1) \\ = 8 \sqrt{2} - 3 \times 6 + \sqrt{3} \\ = 8 \sqrt{2} - 18 + \sqrt{3}$