Question

De calculat timpul caderii si viteza finala a unui corp ce cade la inaltimea de 45m.

Answer 1

$h= \frac{gt^2}{2} \\ 45= \frac{10t^2}{2} \\ 90=10t^2 \\ t=3\ secunde \\ V^2=2gh \\ V^2=900 \\ V=30\ m/s$