Question

De calculat volumul gazului ce se degaja la interactiunea potasiului cu 600g solutie de acid acetic de 30%. de calculat masa sarii obtinute dua reactie

Answer 1

Md/ms=0.3 md/600=0.3 md=600*0.3 md=180 g acid acetic reactioneaza
M ch3-cooh= 2*12 + 2*16+ 4* 1= 24+32+4= 60 g/mol
n ch3-cooh= m/M= 180/60=3 moli
3moli 3moli 3moli 1.5moli
Ch3-cooh + K ---> ch3-cook + 1/2 H2 (gaz)
1 1 1 1/2
Volum gaz degajat= 22.4*1.5= 33.6 L
M ch3-cook= 24+32+3+39= 88 g/mol m= 3*88 = 264 g

Answer 2

Cp=md/ms*100==>md=Cp*ms/100=30*600/100=180g CH3-COOH

n=m/M=180/60=3 moli acid acetic

CH3-COOH + K --> CH3-COOK + 1/2H2

1mol C2H4O2...1mol K.....1mol C2H3O2K...0.5moli H2
3moli....x=3moli...y=3moli....z=1.5 moli H2

n=V/Vmolar==>V=n*Vmolar=1.5*22.4=33.6 L H2

MCH3-COOH=60g/mol