Question

De extrascris radical 3,5,radical4,(5) ,radical 3,2 (12)

Answer 1

$\sqrt{3.5}= \frac{35}{10}= \sqrt{ \frac{7}{2} } = \frac{ \sqrt{7} }{ \sqrt{2} }= \frac{ \sqrt{7} \sqrt{2} }{\sqrt{2}\sqrt{2}}= \frac{\sqrt{14}}{2}$
$\sqrt{4.(5)}=2*5=10$
$\sqrt{3.2(12)}= \sqrt{ \frac{16}{5} }*12=12 \sqrt{ \frac{16}{5} }=12* \frac{4}{ \sqrt{5} }= \frac{12*4}{ \sqrt{5} }= \frac{48}{ \sqrt{5} }= \frac{48 \sqrt{5} }{ \sqrt{5} \sqrt{5}}= \frac{48 \sqrt{5} }{5}$