Question

De la 11.Te rog frumos sa ma ajutati!

Answer 1

$11) \\ \\ a)4 \sqrt{6} + \sqrt{24} - \sqrt{150} + \sqrt{54} = \\ \\ 4 \sqrt{6} + 2 \sqrt{6} - 5 \sqrt{6} + 3 \sqrt{6} = \\ \\ (4 + 2 - 5 + 3) \sqrt{6} = \\ \\ (6 - 2) \sqrt{6} = \\ \\ 4 \sqrt{6}$

$c) \sqrt{300} + \sqrt{75} - 2 \sqrt{147} = \\ \\ 10 \sqrt{3} + 5 \sqrt{3} - 2 \times 7 \sqrt{3} = \\ \\ 10 \sqrt{3} + 5 \sqrt{3} - 14 \sqrt{3} = \\ \\ (10 + 5 - 14) \sqrt{3} = \\ \\ (15 - 14) \sqrt{3} = \\ \\ 1 \sqrt{3} = \\ \\ \sqrt{3}$

$e) \sqrt{72} + 2 \sqrt{98} - 3 \sqrt{242} - \sqrt{32} = \\ \\ 6 \sqrt{2} + 2 \times 7 \sqrt{2} - 3 \times 11 \sqrt{2} - 4 \sqrt{2} = \\ \\ 6 \sqrt{2} + 14 \sqrt{2} - 33 \sqrt{2} - 4 \sqrt{2} = \\ \\ (6 + 14 - 33 - 4) \sqrt{2} = \\ \\ (20 - 37) \sqrt{2} = \\ \\ - 17 \sqrt{2}$

$g) \sqrt{63} - 2 \sqrt{175} + 3 \sqrt{112} + 4 \sqrt{28} = \\ \\ 3 \sqrt{7} - 2 \times 5 \sqrt{7} + 3 \times 4 \sqrt{7} + 2 \times 4 \sqrt{7} = \\ \\ 3 \sqrt{7} - 10 \sqrt{7} + 12 \sqrt{7} + 8 \sqrt{7} = \\ \\ (3 - 10 + 12 + 8) \sqrt{7} = \\ \\ (23 - 10) \sqrt{7} = \\ \\ 13 \sqrt{7}$