Question

De la 31 pe b) si c)

Answer 1

3ab a+b<6
b={0,2,4,6,8}=cifrele pare
b=0
=>a={5,4,3,2,1,0}
b=2
=>a={3,2,1,0}
b=4
=>a=1,0
Numerele:350,340,330,320,310,300,
332,322,312,302
310,300
Numarul numerelor pare =10numere
c)a3b a+b<6
b={1,3,5,7,9}=cifrele impare
b=1
a=4,3,2,1
b=3
a=2,1
Numerele:431,331,231,131
231,131
Numarul numerelor impare:4