Question

De la inaltimea h=180m, cade liber un corp. Cu ce viteza initiala Vo trebuie aruncat al doilea corp, la u interval de timp t=1 s, pentru ca ambele corpuri sa ajunga jos in acelasi timp? (g=10 m/s2

Answer 1

Se da:
h=180m
t'=1s
t1=t2
g=10m/s²
v0=?m/s

Formule:
h=gt1²/2
t1=√(2h/g)

t2=t"+t'
t1=t"+t'
t"=t1-t'

h=v0t"+gt"²/2
v0(t1-t')=h-[g(t1-t')²/2]
v0={h-[g(t1-t')²/2]}/(t1-t')

Calcule:
t1=√(2h/g)=6s
v0={180-[10*(6-1)²/2]}/(6-1)=11m/s