Question

Decat Primele 3 pls dau coroana orice urgent

Answer 1

1.(√2 x+√3)²+(2x-3)²=a=>a=2x²+3+2√6x+4x²+9-12x=6x²+2x(√6-6)+11

2.√(4√5-2√7)*√(4√5+2√7)=√[(4√5-2√7)(4√5+2√7)]=√(100-28)=6√2

3.2√3(1/√3-1/√6)+√2=2√3[(√6-√3)/3√2]+√2=(6√2-6)/3√2+√2=(6√2-6+6)/3√2=6√2/3√2=2