Question

Decât primele subpuncte de la ex:1,2,3

Answer 1

1) 4,3 + 1,3 · 6 = 4,3 + 7,8 = 12,1

2) $3-2\cdot \left(-\dfrac{1}{5}\right) = 3 +2\cdot \dfrac{1}{5} =$

$= \dfrac{15+2}{5} = \dfrac{3\cdot 5+2}{5} = \dfrac{17}{5}$

3) $\dfrac{2}{5}+\left(\dfrac{1}{2}\right)^{-2}\cdot (3,5-0,4) =$

$=\dfrac{2}{5}+2^2\cdot 3,1 = 4\cdot 3,1 =$

$= 0,4+12,4= 12,8$