Question

Deci dau 34 puncte ! Exercitiul 1.20 va rog frumos.

Answer 1

Se da:
I1=0,45A
R1=8ohm
R2=3ohm
R3=6ohm
I2;I3=?A

Formule:
I2=U2/R2

U2=U1=U23

U23=R23*I23

I23=I1

1/R23=(1/R2)+(1/R3)
1/R23=(R2+R3)/(R2*R3)
R23=R2*R3/(R2+R3)

I2=U23/R2
I3=U23/R3

Calcule:
R23=3*6/(3+6)=2ohm
U23=2*0,45=0,9V
I2=0,9/3=0,3A
I3=0,9/6=0,15A