Question

deminstrati ca 4la puterea 2n+2 la puterea 2n+1. +1. n apartine N este patrat perfect.

Answer 1

[tex]4^{2n}+2^{2n+1}+1=\\ =(2^n)^2+2^{2n}\cdot 2+1^2=(2^{2n}+1)^2p.p.\\ [/tex]