Question

demonstrati ca  abc(cu bara sus)+bca(bara sus)+cab(bara sus) se divide cu 37

Answer 1

abc+bca+cab=100a+10b+c+100b+10c+a+100c+10a+b=111a+111b+111c=111(a+b+c)=37*3(a+b+c)=> numarul se divide cu 37.