Question

Demonstrati ca in orice triunghi dreptunghic ABC (m(<A)=90 grade) are loc relatia sin B+ cos B=sin C + cos C.Ajutati-ma va rog!!

Answer 1

[tex]sin B= \frac{AC}{BC}; sin C= \frac{AB}{BC}; cosB= \frac{AB}{BC}; cosC= \frac{AC}{BC} => [/tex]$sinB+cosB= \frac{AC+AB}{BC} ;sinC+cosC= \frac{AB+AC}{BC}$
Cele doua ecuatii sunt egale.