Question

demonstreaza ca numarul a este patrat perfect,unde: a=1+2+3+......+100

Answer 1

a=1+2+3+......+100
a=100x101/2
a=5050
√a≈71,06 (F)

Answer 2

Aplicam Suma Gauss

a=1+2+3+...+100=
a=100*101/2=
a=10100/2=
a=5050

$Patrat-Perfect= x^{2}$
$x=71,06(radical) \\ Nu-este-Patrat-Perfect.$