Question

demonstreaza ca numarul x=abb + baa este divibil cu 111

Answer 1

x=abb+baa
=100a+10b+b+100b+10a+a
=111a+111b
=111(a+b) / 111

Answer 2

x=abb+baa
x=100a+10b+b+100b+10a+a
x=111a+111b
x=111*(a+b) ⇒ x divizibil cu 111