Question

demonstreaza ca x este triplul numarului y ,cunoscand relatiile.
{288-72:[4 +2•(18-x:27)]•24}:15=16

70-{60•[145-(50-2y)•10 ]+84}:6=6

Answer 1

Răspuns

{288-72:[4+2*(18-x:27)]*24}:15=16

288-72:[4+2*(18-x:27)]*24=16*15

288-72:[4+2*(18-x:27)]*24=240

72:[4+2*(18-x:27)]*24=288-240

72:[4+2*(18-x:27)]*24=48

72:[4+2*(18-x:27)]=48:24

72:[4+2*(18-x:27)]=2

4+2*(18-x:27)=72:2

4+2*(18-x:27)=36

2*(18-x:27)=36-4

2*(18-x:27)=32

18-x:27=32:2

18-x:27=16

x:27=18-16

x:27=2

x=27*2

x=54

70-{60•[145-(50-2y)•10 ]+84}:6=6

{60•[145-(50-2y)•10 ]+84}:6=70-6

{60•[145-(50-2y)•10 ]+84}:6=64

60•[145-(50-2y)•10 ]+84=64*6

60•[145-(50-2y)•10 ]+84=384

60•[145-(50-2y)•10 ]=384-84

60•[145-(50-2y)•10]=300

145-(50-2y)•10=300:60

145-(50-2y)•10=5

(50-2y)•10=145-5

(50-2y)•10=140

50-2y=140:10

50-2y=14

2y=50-14

2y=36

y=36:2

y=18

x=3y=18*3=54