Question

denumiti urmatoarele substante si calculati masa molecurala ,raport atomic , raport de masa , Mg(OH)2 SO3 H3PO3 Na2O Mg(NO3)2 NH4NO3 H2S Na2CO3 Al2(SO4)3 Ca3(PO3)2


Ajutatima!!!!!! dau 10 punte

Answer 1

Explicație:

Mg(OH)2 hidroxid de magneziu

MMg(OH)2=24+2×16+2×1=58

r.at.Mg:O:H=1:2:2

r.m. Ng:O:H=24:32:2=12:16:1

SO3 trioxid de sulf

MSO3=32+3×16=80

r.at. S:O=1:3

r.m S:O=32:48=2:3

H3PO3 acid fosforos

MH3PO3 =3×1+31+3×16=82

r.at. H:P:O = 3:1:3

r.m. H:P:O= 3:31:48

Na2O oxid de sodiu

MNa2O=2×23+16=62

r.at. Na:O=2:1

r.m. Na:O=46:16=23:8

Mg(NO3)2 azotat de magneziu

MMg(NO3)2=24+2×14+6×16=148

rrat.Mg:N:O=1:2:6

r.m.Mg::N;O=24:28:96=12:14:48

NNH4NO3 azotat de amoniu

MNH4NO3=2×14+4×1+3×16=76

r.at.N:H:N:O=1:4:1:3

r.m.N:H:N:O=14:4:14:48

H2S acid sulfhidric

MH2S=2×1+32=34

r.at.H:S=2:1

r.m.H:S=2:32=1:16

Na2CO3 carbonat de sodiu

MNa2CO3 =2×23+12+3×16=106

r.at.Na:C:O=2:1:3

r.m.Na:C:O=46:12:48=23:6:24

Al2SO4)3 sulfat de aluminiu

MMAl2(SO4)3=2×27+3×32+12×16=342

r.at.Al:S:O=2:3:12

r.m. Al:S:O=54:96:192

Ca3(PO4(2 fosfat de calciu

MCa3(PO4)2=3×40+2×31+8×16=310

r.at. Ca: P: O=3:2:8

r.m. Ca:P:O=120:62:128=110:31:64